22b^2-34b-20=1

Solution for 22b^2-34b-20=1 equation:

22b^2-34b-20=1

We move all terms to the left:

22b^2-34b-20-(1)=0

We add all the numbers together, and all the variables

22b^2-34b-21=0

a = 22; b = -34; c = -21;
Δ = b2-4ac
Δ = -342-4·22·(-21)
Δ = 3004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3004}=\sqrt{4*751}=\sqrt{4}*\sqrt{751}=2\sqrt{751}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2\sqrt{751}}{2*22}=\frac{34-2\sqrt{751}}{44}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2\sqrt{751}}{2*22}=\frac{34+2\sqrt{751}}{44}
$